document.write( "Question 126583: The length of a rectangle is 50 ft. The perimeter of the rectangle is 275 ft. more than the width of the rectangle. Find the width \n" ); document.write( "
Algebra.Com's Answer #92733 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2*50+2W=275-W \n" ); document.write( "100+2W=275-W \n" ); document.write( "2W+W=275-100 \n" ); document.write( "3W=175 \n" ); document.write( "W=175/3 \n" ); document.write( "W=58.33 ANSWER FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*50+2*58.33=275-58.33 \n" ); document.write( "100+116.66=216.67 \n" ); document.write( "216.66=216.67 \n" ); document.write( " \n" ); document.write( " |