document.write( "Question 126583: The length of a rectangle is 50 ft. The perimeter of the rectangle is 275 ft. more than the width of the rectangle. Find the width \n" ); document.write( "
Algebra.Com's Answer #92733 by checkley71(8403)\"\" \"About 
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2*50+2W=275-W
\n" ); document.write( "100+2W=275-W
\n" ); document.write( "2W+W=275-100
\n" ); document.write( "3W=175
\n" ); document.write( "W=175/3
\n" ); document.write( "W=58.33 ANSWER FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*50+2*58.33=275-58.33
\n" ); document.write( "100+116.66=216.67
\n" ); document.write( "216.66=216.67
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