document.write( "Question 126568: In a chemistry class, 12 L of a 12% alcohol solution must be mixed with a 2% solution to get a 14% solution. How many liters of the 20% solution are needed? \n" ); document.write( "

Algebra.Com's Answer #92725 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(amount of alcohol needed) / (total amount of solution) = 20%
\n" ); document.write( "In the 12% solution I have
\n" ); document.write( " $\"12%2A.12+=+1.44\"$ liters alcohol
\n" ); document.write( "Let $\"x\"$ be the amount of 20% solution needed
\n" ); document.write( " $\"%281.44+%2B+.2x%29+%2F+%2812+%2B+x%29+=+.14\"$
\n" ); document.write( " $\"1.44+%2B+.2x+=+.14%2812+%2B+x%29\"$
\n" ); document.write( " $\"1.44+%2B+.2x+=+1.68+%2B+.14x\"$
\n" ); document.write( " $\".06x+=+.24\"$
\n" ); document.write( " $\"x+=+4\"$
\n" ); document.write( "4 liters of the 20% solution are needed
\n" ); document.write( "check
\n" ); document.write( " $\"%281.44+%2B+.2x%29+%2F+%2812+%2B+x%29+=+.14\"$
\n" ); document.write( " $\"%281.44+%2B+.2%2A4%29+%2F+%2812+%2B+4%29+=+.14\"$
\n" ); document.write( " $\"%281.44+%2B+.8%29+%2F+16+=+.14\"$
\n" ); document.write( " $\"2.24+%2F+16+=+.14\"$
\n" ); document.write( " $\".14+=+.14\"$
\n" ); document.write( "OK \n" ); document.write( "

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