document.write( "Question 126569This question is from textbook Amscos Preparing for the Regents Examination Mathematics B
\n" ); document.write( ": Solve for x
\n" ); document.write( "Log6(x) = log6(36) - log6(1/6)\r
\n" ); document.write( "\n" ); document.write( "please explain and show work thanks \n" ); document.write( "
Algebra.Com's Answer #92724 by stanbon(75887)\"\" \"About 
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Log6(x) = log6(36) - log6(1/6)\r
\n" ); document.write( "\n" ); document.write( "Keep in mind that the base is 6 for all the work:
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\n" ); document.write( "log(x) = log(36) - log(1/6)
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\n" ); document.write( "Rule: log(a)-log(b) = log(a/b)
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\n" ); document.write( "log(x) = log [36/(1/6)]
\n" ); document.write( "log(x) = log[216]
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\n" ); document.write( "Since the logs are equal, the anti-logs are equal:
\n" ); document.write( "x = 216
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\n" ); document.write( "Another way to do it:
\n" ); document.write( "log6(x) = 2 -(-1)
\n" ); document.write( "log6(x) = 3
\n" ); document.write( "x = 6^3
\n" ); document.write( "x = 216
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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