document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126563>Question 126563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is -48. The first number is twelve more than the second number,and the third number is 20 less than twice the second number. Find the three numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92710 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z=-48 <BR>\n" );
document.write( "x=y+12 <BR>\n" );
document.write( "z=2y-20 <BR>\n" );
document.write( "Replacing x & z with (y+12) & (2y-20)<BR>\n" );
document.write( "(y+12)+y+(2y-20)=-48<BR>\n" );
document.write( "y+12+y+2y-20=-48<BR>\n" );
document.write( "4y=-48-12+20<BR>\n" );
document.write( "4y=-40<BR>\n" );
document.write( "y=-40/4<BR>\n" );
document.write( "y=-10 answer.<BR>\n" );
document.write( "x=-10+12=2 answer.<BR>\n" );
document.write( "z=2*-10-20=-20-20=-40 answer.<BR>\n" );
document.write( "PROOF.<BR>\n" );
document.write( "-10+2-40=-48<BR>\n" );
document.write( "-48=-48 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );