document.write( "Question 126563: The sum of three numbers is -48. The first number is twelve more than the second number,and the third number is 20 less than twice the second number. Find the three numbers \n" ); document.write( "
Algebra.Com's Answer #92708 by marcsam823(57)![]() ![]() ![]() You can put this solution on YOUR website! Let x = second number \n" ); document.write( "Let x + 12 = first number \n" ); document.write( "Let 2x - 20 = third number (twenty less than two times the second\r \n" ); document.write( "\n" ); document.write( "Set up the equation - the sum of the numbers is: \n" ); document.write( "1st number + 2nd number + 3rd number = -48 \n" ); document.write( " \n" ); document.write( "Combine like terms and solve: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-10 is the SECOND number \n" ); document.write( "Substite: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This checks out. The three numbers are -10, 2 and -40 \n" ); document.write( " \n" ); document.write( " |