document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126432>Question 126432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -x+10y=11<BR>\n" );
document.write( "graph linear equation \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92674 by </B><A HREF=/tutors/aboutme.mpl?userid=JessicaGill><B>JessicaGill(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JessicaGill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Graphing linear equations is relatively simple if you first rewrite the equation into the slope-intercept formula  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=mx%2Bb ALIGN=MIDDLE  ALT=\"y=mx%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  For this equation, we can do the following.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x%2B10y=11 ALIGN=MIDDLE  ALT=\"-x%2B10y=11\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "First add x to each side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x%2Bx%2B10y=11%2Bx ALIGN=MIDDLE  ALT=\"-x%2Bx%2B10y=11%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10y=11%2Bx ALIGN=MIDDLE  ALT=\"10y=11%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Second, we can divide both sides by 10 to isolate the y variable.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10y%2F10=11%2F10%2Bx%2F10 ALIGN=MIDDLE  ALT=\"10y%2F10=11%2F10%2Bx%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=11%2F10%2Bx%2F10 ALIGN=MIDDLE  ALT=\"y=11%2F10%2Bx%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=1%2F10x%2B11%2F10 ALIGN=MIDDLE  ALT=\"y=1%2F10x%2B11%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now we have a y intercept to graph and also the slope to find a second point from the y intercept location.\r<BR>\n" );
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document.write( "The y intercept is (0,11/10) and the slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=rise%2Frun ALIGN=MIDDLE  ALT=\"rise%2Frun\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F10%29 ALIGN=MIDDLE  ALT=\"%281%2F10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Once the y intercept is graphed, from that point follow up  one unit and then to the right 11 units to get your next point.  Connect the points with a line.  It would be helpful for you to lable your points in case there is any question as to what you intended to show for your answer.\r<BR>\n" );
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document.write( "Please see the graph below for an approximation on how you line will look\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C+300%2C+-20%2C+20%2C+-20%2C+20%2C+y=%281%2F10%29x%2B%2811%2F10%29%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C+300%2C+-20%2C+20%2C+-20%2C+20%2C+y=%281%2F10%29x%2B%2811%2F10%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
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