document.write( "Question 126449: A person invested $10,000.00. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160.00 more than the annual income from the smaller part. What is the smaller part of the investment? \n" ); document.write( "
Algebra.Com's Answer #92671 by checkley71(8403)\"\" \"About 
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.06x=.05(10,000-x)+160
\n" ); document.write( ".06x=500-.05x+160
\n" ); document.write( ".06x+.05x=660
\n" ); document.write( ".11x=660
\n" ); document.write( "x=660/.11
\n" ); document.write( "x=6000 the amount invested @ 6%
\n" ); document.write( "10,000-6,000=4,000 invested @ 5%
\n" ); document.write( "PROOF:
\n" ); document.write( ".06*6000=.05(4,000)+160
\n" ); document.write( "360=200+160
\n" ); document.write( "360=360
\n" ); document.write( "
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