document.write( "Question 126468: A piece of sculpture is purchased for $3000 in 1960. In 2008,the sculpture is valued at $186000. What is the average annual rate of appreciation of the sculpture? \n" ); document.write( "
Algebra.Com's Answer #92661 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 186,000=3000(1+r)^48 \n" ); document.write( "186,000=3000(1+.089787)^48 \n" ); document.write( "186,000=3000(62) \n" ); document.write( "186,000=186,000 \n" ); document.write( "Answer is 8.9787%. \n" ); document.write( " |