document.write( "Question 126467: If 2% of students are basketball players and 31% of basketball players have an 'A' average what is the probability that a student chosen at random will be a basketball player with an 'A' average? \n" ); document.write( "
Algebra.Com's Answer #92654 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If 2% of students are basketball players and 31% of basketball players have an 'A' average what is the probability that a student chosen at random will be a basketball player with an 'A' average? \n" ); document.write( "--------------- \n" ); document.write( "Assuming that being a basketball player and getting an A are independent \n" ); document.write( "events you get: \n" ); document.write( "P(b and A) = P(b)*P(A) = 0.02*0.31 = 0.0062 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |