document.write( "Question 126444This question is from textbook Intermediate Algebra Review
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document.write( ": Let h(t)=5-t^2, evaluate the following. Write your answers as order pairs.\r
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document.write( "h(2/3) \n" );
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Algebra.Com's Answer #92631 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! You are given: \n" ); document.write( ". \n" ); document.write( "h(t) = 5 - t^2 \n" ); document.write( ". \n" ); document.write( "and you are to find h(2/3). All this is telling you to do is to go to the given function \n" ); document.write( "for h(t) and for both sides wherever you see a \"t\" you substitute 2/3. Then you just \n" ); document.write( "simplify the terms. \n" ); document.write( ". \n" ); document.write( "In this problem you start with the function: \n" ); document.write( ". \n" ); document.write( "h(t) = 5 - t^2 \n" ); document.write( ". \n" ); document.write( "for every t in this function you substitute 2/3 and you get: \n" ); document.write( ". \n" ); document.write( "h(2/3) = 5 - (2/3)^2 \n" ); document.write( ". \n" ); document.write( "Next, on the right side square the 2/3 and you get 4/9. Substitute 4/9 for (2/3)^2 and \n" ); document.write( "the result is: \n" ); document.write( ". \n" ); document.write( "h(2/3) = 5 - 4/9 \n" ); document.write( ". \n" ); document.write( "Finally, subtract 4/9 from 5 [equivalent to subtracting 4/9 from 4 9/9] and you get the \n" ); document.write( "answer 4 5/9 ... that's read as \"4 and 5-ninths\" and it's equivalent to 41/9. \n" ); document.write( ". \n" ); document.write( "So the answer to this problem is: \n" ); document.write( ". \n" ); document.write( "h(2/3) = 4 5/9 = 41/9 \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the process of evaluating a function and what the notation \n" ); document.write( "means. In this case h(2/3) means \"find the value of h(t) when t equals 2/3.\" \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |