document.write( "Question 126444This question is from textbook Intermediate Algebra Review
\n" ); document.write( ": Let h(t)=5-t^2, evaluate the following. Write your answers as order pairs.\r
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Algebra.Com's Answer #92631 by bucky(2189)\"\" \"About 
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You are given:
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\n" ); document.write( "h(t) = 5 - t^2
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\n" ); document.write( "and you are to find h(2/3). All this is telling you to do is to go to the given function
\n" ); document.write( "for h(t) and for both sides wherever you see a \"t\" you substitute 2/3. Then you just
\n" ); document.write( "simplify the terms.
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\n" ); document.write( "In this problem you start with the function:
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\n" ); document.write( "h(t) = 5 - t^2
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\n" ); document.write( "for every t in this function you substitute 2/3 and you get:
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\n" ); document.write( "h(2/3) = 5 - (2/3)^2
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\n" ); document.write( "Next, on the right side square the 2/3 and you get 4/9. Substitute 4/9 for (2/3)^2 and
\n" ); document.write( "the result is:
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\n" ); document.write( "h(2/3) = 5 - 4/9
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\n" ); document.write( "Finally, subtract 4/9 from 5 [equivalent to subtracting 4/9 from 4 9/9] and you get the
\n" ); document.write( "answer 4 5/9 ... that's read as \"4 and 5-ninths\" and it's equivalent to 41/9.
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\n" ); document.write( "So the answer to this problem is:
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\n" ); document.write( "h(2/3) = 4 5/9 = 41/9
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\n" ); document.write( "Hope this helps you to understand the process of evaluating a function and what the notation
\n" ); document.write( "means. In this case h(2/3) means \"find the value of h(t) when t equals 2/3.\"
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