document.write( "Question 19232: \"x\" varies direcly as the square of \"s\" and inversely as \"t\". How does \"x\" change when \"s\" is doubled? When both \"s\" and \"t\" are doubled?
\n" ); document.write( "I figured \"x\" = \"k\" \"s\" squared divided by \"t\" (using \"k\" as a non zero constant but I'm stuck.
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Algebra.Com's Answer #9263 by Earlsdon(6294)\"\" \"About 
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Try this:
\n" ); document.write( "\"x+=+ks%5E2%2Ft\" Multipy s by 2.
\n" ); document.write( "\"x+=+k%282s%29%5E2%2Ft\" = \"4%28ks%5E2%29%2Ft+=+4x\" So, x is quadrupled when s is doubled.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+ks%5E2%2Ft\" Multiply s and t by 2.
\n" ); document.write( "\"x+=+k%282s%29%5E2%2F2t\"
\n" ); document.write( "\"x+=+4ks%5E2%2F2t\" = \"2ks%5E2%2Ft+=+2x\" So, x is doubled when both s and t are doubled.
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