document.write( "Question 126374: In a collection of dimes and quarters, there are seven more quarters than dimes. How many dimes and quarters are there if the collection is worth $3.50?
\n" ); document.write( "What is the equation for this?
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Algebra.Com's Answer #92594 by solver91311(24713)\"\" \"About 
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The question should have been \"what are the equations for this?\"\r
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\n" ); document.write( "\n" ); document.write( "You have a situation where you can express a relationship between the numbers of things and another relationship between the values of those things. Meaning that you will have to develop a system of equations and solve them.\r
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\n" ); document.write( "\n" ); document.write( "Let q be the number of quarters and d be the number of dimes. The quantity relationship is \"q+=+d+%2B+7\" because there are 7 more quarters than dimes.\r
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\n" ); document.write( "\n" ); document.write( "Each quarter is worth 25 cents so the total value of q quarters in cents is 25q. Likewise for the dimes, the total value is 10d. We know that the total value of all the coins is $3.50 or 350 cents, so we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"25q+%2B+10d+=+350\"\r
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\n" ); document.write( "\n" ); document.write( "Into this equation we can substitute the expression for the number of quarters in terms of dimes:\r
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\n" ); document.write( "\n" ); document.write( "\"25%28d%2B7%29%2B10d=350\"
\n" ); document.write( "\"25d%2B175%2B10d=350\"
\n" ); document.write( "\"35d%2B175=350\"
\n" ); document.write( "\"35d=175\"
\n" ); document.write( "\"d=5\"\r
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\n" ); document.write( "\n" ); document.write( "So there are 5 dimes. Since there are 5 dimes, there must be \"5%2B7=12\" quarters.\r
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\n" ); document.write( "\n" ); document.write( "Check.\r
\n" ); document.write( "\n" ); document.write( "\"25%2A12=300\"
\n" ); document.write( "\"10%2A5=50\"\r
\n" ); document.write( "\n" ); document.write( "\"300%2B50=350\"
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