document.write( "Question 126377: Help please I can not figure this out! Thanks so much.
\n" ); document.write( "The perimeter of a rectangle 48m. The length is 9m more than twice the width. What is the length please? Thank you for your help.
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Algebra.Com's Answer #92592 by solver91311(24713)\"\" \"About 
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Let the length be x, because that is the answer we want. The length is 9 more than twice the width, so the width is expressed by \"%28x-9%29%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is \"P=2L%2B2W\".\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B2%28%28x-9%29%2F2%29=48\" because we are given that the perimeter is 48.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2Bx-9=48\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=57\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=19\". The length is 19 meters.\r
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\n" ); document.write( "\n" ); document.write( "Check the answer. If the length is 19 meters, then the width has to be \"%2819-9%29%2F2=5\". \"2%2A19%2B2%2A5=38%2B10=48\". Answer checks.
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