document.write( "Question 126344: I don't really know where to place this problem, because it comes in the guide of a contest exam, so I don't know what theme are they talking about, but the problem is like this:
\n" ); document.write( "If (x+y)^2=17 and xy=3, then x^2+y^2=
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\n" ); document.write( "b.17
\n" ); document.write( "c.14
\n" ); document.write( "d.11\r
\n" ); document.write( "\n" ); document.write( "Can you tell me which theme are they talking about and how to solve it... Thank you...
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Algebra.Com's Answer #92540 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2By%29%5E2=17\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2xy%2By%5E2=17\" Foil the left side\r
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\n" ); document.write( "\n" ); document.write( "Notice how the second equation is \"xy=3\" and the 2nd step has an \"2xy\" term in it. So let's multiply both sides of \"xy=3\" by 2\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Axy=2%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2xy=6\"\r
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\n" ); document.write( "\n" ); document.write( "So this means we can replace the \"2xy\" term in \"x%5E2%2B2xy%2By%5E2=17\" with 6\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6%2By%5E2=17\" Replace \"2x\" with 6\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bcross%286-6%29%2By%5E2=17-6\" Subtract 6 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2=11\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x%5E2%2By%5E2=11\" which means that the answer is D)
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