document.write( "Question 126231: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE THE TWO WILL MEET IF THE HOUSES ARE 4 MILES APART? \n" ); document.write( "
Algebra.Com's Answer #92506 by josmiceli(19441)\"\" \"About 
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First think about what is generally true. They meet
\n" ); document.write( "somewhere in the middle, so the sum of their walks
\n" ); document.write( "is 4 miles. They leave at the same time, so the
\n" ); document.write( "time each spends walking is exactly the same.
\n" ); document.write( "Now you can start
\n" ); document.write( "Let \"d%5Bf%5D\" = distance in miles Fred walks
\n" ); document.write( "Let \"d%5Bj%5D\" = distance in miles Jon walks
\n" ); document.write( "\"d%5Bf%5D+%2B+d%5Bj%5D+=+4\" what I just said
\n" ); document.write( "Let \"t\" = time in hours they both spend walking
\n" ); document.write( "\"d%5Bf%5D+=+3t\"
\n" ); document.write( "\"d%5Bj%5D+=+2t\"
\n" ); document.write( "Now add these equations
\n" ); document.write( "\"d%5Bf%5D+%2B+d%5Bj%5D+=+3t+%2B+2t\"
\n" ); document.write( "\"4+=+3t+%2B+2t\"
\n" ); document.write( "\"5t+=+4\"
\n" ); document.write( "\"t+=+4%2F5\" hr
\n" ); document.write( "or
\n" ); document.write( "They will meet in \"%284%2F5%2960+=+48\" minutes answer
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