document.write( "Question 126199: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #92502 by checkley71(8403)\"\" \"About 
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.05x+.03(18000-x)=660
\n" ); document.write( ".05x+540-.03x=660
\n" ); document.write( ".02x=660-540
\n" ); document.write( ".02x=120
\n" ); document.write( "x=120/.02
\n" ); document.write( "x=6000 amount invested @ 5%.
\n" ); document.write( "18000-6000=12000 invested @ 3%.
\n" ); document.write( "proof:
\n" ); document.write( ".05*6000+.03*12000=660
\n" ); document.write( "300+360=660
\n" ); document.write( "660=660
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