document.write( "Question 126199: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #92502 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .05x+.03(18000-x)=660 \n" ); document.write( ".05x+540-.03x=660 \n" ); document.write( ".02x=660-540 \n" ); document.write( ".02x=120 \n" ); document.write( "x=120/.02 \n" ); document.write( "x=6000 amount invested @ 5%. \n" ); document.write( "18000-6000=12000 invested @ 3%. \n" ); document.write( "proof: \n" ); document.write( ".05*6000+.03*12000=660 \n" ); document.write( "300+360=660 \n" ); document.write( "660=660 \n" ); document.write( " \n" ); document.write( " |