document.write( "Question 2201: 1. 9(x-5)-x(x-5)=
\n" ); document.write( "2. ax+ay+2bx+2by=
\n" ); document.write( "3. ma+mb+na+nb=
\n" ); document.write( "Can you solve and tell me how to do these three problems on factoring?
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Algebra.Com's Answer #925 by gsmani_iyer(201)\"\" \"About 
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1. 9(x-5)-x(x-5)
\n" ); document.write( " = (x-5)(9-x) Answer.\r
\n" ); document.write( "\n" ); document.write( "2 ax+ay+2bx+2by
\n" ); document.write( " = a(x+y)+2b(x+y)
\n" ); document.write( " = (x+y)(a-2b) Ans.\r
\n" ); document.write( "\n" ); document.write( "3. ma+mb+na+nb
\n" ); document.write( " = m(a+b)+n(a+b)
\n" ); document.write( " = (a+b)(m+n) Ans.\r
\n" ); document.write( "\n" ); document.write( " Try to take out the common term first. In the first problem, (x-5) is the common term. Take the common term as one factor and take the coefficients as the other factor. Here, in this case, 9 and -x are the coefficients. Take it as it is in order which comes to (9-x). That's all.
\n" ); document.write( " In the 2nd & 3rd problems, split out the expression into 2 terms each in such a way that in each two terms you have a common variable and factorise them.
\n" ); document.write( "Then again, take out the common term as one factor and the coefficients as another.
\n" ); document.write( " I hope you understood the basic principle of solving such problems. O.K
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