document.write( "Question 126180: how do you solve y=x-2 y=4x+1 \n" ); document.write( "
Algebra.Com's Answer #92496 by ankor@dixie-net.com(22740)\"\" \"About 
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how do you solve y=x-2 y=4x+1
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\n" ); document.write( "Here it is step-by-step, if you learn these, you will know.
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\n" ); document.write( "Since y = (x-2) we can substitute (x-2) for y in the 2nd equation and find x:
\n" ); document.write( "x - 2 = 4x + 1
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\n" ); document.write( "We want to do what is necessary to get x by itself on one side of the equation
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\n" ); document.write( "Subtract x from both sides
\n" ); document.write( "x -x - 2 = 4x -x + 1
\n" ); document.write( "-2 = 3x + 1
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\n" ); document.write( "Subtract 1 from both sides
\n" ); document.write( "-2 - 1 = 3x +1 -1
\n" ); document.write( "-3 = 3x
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\n" ); document.write( "We usually write it with x on the left:
\n" ); document.write( "3x = - 3
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\n" ); document.write( "Divide both sides by 3, that makes it 1x or we can just write x
\n" ); document.write( "x = \"-3%2F3\"
\n" ); document.write( "x = -1
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\n" ); document.write( "Use y = x - 2 to find y, substitute -1 for x
\n" ); document.write( "y = -1 - 2
\n" ); document.write( "y = -3
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\n" ); document.write( "Check solutions by substituting for x and y in the 2nd equation
\n" ); document.write( "y = 4x + 1
\n" ); document.write( "Substituting for x & y
\n" ); document.write( "-3 = 4(-1) + 1
\n" ); document.write( "-3 = -4 + 1
\n" ); document.write( "-3 = -3; Equal! so we know our solutions are correct
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\n" ); document.write( "Any questions?
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