document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126235>Question 126235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^2+12x+5=p(x+q)^2+r\r<BR>\n" );
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document.write( "find values for p,q and r\r<BR>\n" );
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document.write( "I appreciate any form of help you can give me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92486 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^2+12x+5=p(x+q)^2+r\r<BR>\n" );
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document.write( "Consider the left side:<BR>\n" );
document.write( "3x^2 + 12x + 5<BR>\n" );
document.write( "= 3(x^2 + 4x) + 5<BR>\n" );
document.write( "= 3(x^2 + 4x + 4 - 4) + 5 [ add and subtract to make it a perfect square]<BR>\n" );
document.write( "=3(x^2 + 4x + 4) - 12 + 5<BR>\n" );
document.write( "= 3(x+2)^2 - 7<BR>\n" );
document.write( "= p(x+q)^2 + r\r<BR>\n" );
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document.write( "Equating, we get, p = 3,  q = 2,  r = -7\r<BR>\n" );
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document.write( "good luck!!!<BR>\n" );
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