document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126221>Question 126221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary if their sum is 90 degrees. the second angle is 6 less then the 3times the first. find the two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92485 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first angle be x<BR>\n" );
document.write( "Then the second angle = 3x - 6\r<BR>\n" );
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document.write( "As they are complementary, their sum is 90 degrees<BR>\n" );
document.write( "==> x + 3x - 6 = 90<BR>\n" );
document.write( "==> 4x = 90 + 6<BR>\n" );
document.write( "==> 4x = 96<BR>\n" );
document.write( "==> x = 96/4<BR>\n" );
document.write( "==> x = 24\r<BR>\n" );
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document.write( "Thus the first angle = 24 deg<BR>\n" );
document.write( "Second angle = 3(24) - 6<BR>\n" );
document.write( "             = 66 deg\r<BR>\n" );
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document.write( "good luck!!! </SPAN>\n" );
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