document.write( "Question 126227: solve the system by addition method. if a unique solution doesn't exist, state whether the system is inconsistent or dependent.
\n" ); document.write( "2x-3y+z=5
\n" ); document.write( "x+4y-2z=-3
\n" ); document.write( "4x-2y+3z=6\r
\n" ); document.write( "\n" ); document.write( "I could really use some. I am pulling out my hair. Please. \n" ); document.write( "
Algebra.Com's Answer #92481 by uma(370)\"\" \"About 
You can put this solution on YOUR website!
2x-3y+z=5 -----------(1)
\n" ); document.write( "x+4y-2z=-3 -------------(2)
\n" ); document.write( "4x-2y+3z=6 --------------(3)\r
\n" ); document.write( "\n" ); document.write( "(2) + (1)*2 gives, 5x - 2y = 7 ------------(4)\r
\n" ); document.write( "\n" ); document.write( "(1)*3 - (3) gives, 2x - 7y = 9 -------------(5)\r
\n" ); document.write( "\n" ); document.write( "Now the equationsa are reduced to 2 in 2 variables.\r
\n" ); document.write( "\n" ); document.write( "(4) * 2 gives, 10x - 4y = 14
\n" ); document.write( "(5) * 5 gives, 10x - 35y = 45\r
\n" ); document.write( "\n" ); document.write( "Subtracting the above 2 equations, we get, 31 y = - 31
\n" ); document.write( "==> y = -1\r
\n" ); document.write( "\n" ); document.write( "Plugging this in (4) gives, 5x + 2 = 7
\n" ); document.write( "==> 5x = 7 - 2
\n" ); document.write( "==> 5x = 5
\n" ); document.write( "==> x = 1\r
\n" ); document.write( "\n" ); document.write( "Substituting x = 1, y = -1 in (1) , 2 + 3 + z = 5
\n" ); document.write( "==> 5 + z = 5
\n" ); document.write( "==> z = 5 - 5
\n" ); document.write( "==> z = 0\r
\n" ); document.write( "\n" ); document.write( "Thus x = 1, y = -1, z = 0\r
\n" ); document.write( "\n" ); document.write( "Good luck!!!
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