document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=126207>Question 126207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried this problem about 10 different ways but I can't seem to get it!! Help!!!\r<BR>\n" );
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document.write( "A merchant has coffee worth $20 a pound that she wishes to mix with 30 pounds of coffee worth $90 a pound to get a mixture that can be sold for $40 a pound. How many pounds of the $20 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92480 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the pounds of $20 coffee necessary.<BR>\n" );
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document.write( "30*90=2700<BR>\n" );
document.write( "x *20=20x<BR>\n" );
document.write( "(30+x)*40=1200+40x<BR>\n" );
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document.write( "20x+2700=40x+1200<BR>\n" );
document.write( "20x=1500<BR>\n" );
document.write( "x=75 lbs.<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "75+30=105 lbs<BR>\n" );
document.write( "75*20=1500<BR>\n" );
document.write( "1500+2700=4200<BR>\n" );
document.write( "105*40=4200<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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