document.write( "Question 126200: a a+b
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document.write( "- + ---
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document.write( "b a-b
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document.write( "_______
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document.write( "a a-b
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document.write( "- - ---
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document.write( "b a+b
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document.write( "In other terms:
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document.write( "[(a/b)+(a+b)/(a/b)]/[(a/b)-(a-b)/(a+b)]\r
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document.write( "I tried to multiply both denominator and numerator by [b(a+b)(a-b)}\] but that didnt seem to work for me. \n" );
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Algebra.Com's Answer #92475 by stanbon(75887) ![]() You can put this solution on YOUR website! [(a/b)+(a+b)/(a-b)]/[(a/b)-(a-b)/(a+b)] \r \n" ); document.write( "\n" ); document.write( "= {[a(a-b)+b(a+b)]/[b(a-b)]} / {[a(a+b)-b(a-b)]/[b(a+b)]\r \n" ); document.write( "\n" ); document.write( "= {[a^2+b^2]/b(a-b)]} / {[a^2-b^2]/[b(a+b)]}\r \n" ); document.write( "\n" ); document.write( "Invert the denominator and multiply after cancelling where you can:\r \n" ); document.write( "\n" ); document.write( "= (a^2+b^2)\r \n" ); document.write( "\n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |