document.write( "Question 126034: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. \n" ); document.write( "
Algebra.Com's Answer #92413 by checkley71(8403) ![]() You can put this solution on YOUR website! 4B-8=ONE OF THE EQUAL LEGS. \n" ); document.write( "THUS THE PERIMETER IS: \n" ); document.write( "2(4B-8)+B=29 \n" ); document.write( "8B-16+B=29 \n" ); document.write( "9B=29+16 \n" ); document.write( "9B=45 \n" ); document.write( "B=45/9 \n" ); document.write( "B=5 ANSWER FOR THE LENGTH OF THE BASE. \n" ); document.write( "4*5-8=12 FOR EACH OF THE EQUAL LEGS. \n" ); document.write( "PROOF \n" ); document.write( "2*12+5=29 \n" ); document.write( "24+5=29 \n" ); document.write( "29=29 \n" ); document.write( " \n" ); document.write( " |