document.write( "Question 19193: how would you solve tjis equation? Square root 4x^2+x-3=2x
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Algebra.Com's Answer #9239 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Hint: When you want to show the square root of a quantity, enclose that quantity in parentheses, thus: Square root(4x^2+x-3) = 2x\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%284x%5E2%2Bx-3%29+=+2x\" Square both sides.
\n" ); document.write( "\"4x%5E2%2Bx-3+=+4x%5E2\" Subtract 4x^2 from both sides.
\n" ); document.write( "\"x-3+=+0\" Add 3 to both sides.
\n" ); document.write( "\"x+=+3\"
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