document.write( "Question 19184: A movie theater sells adult tickets at $5.50 a ticket and $3.50 for a childs ticket. How many of each ticket was sold if 21 tickets were bought for $83.50 \n" ); document.write( "
Algebra.Com's Answer #9238 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! adults = x \n" ); document.write( "childern = y \n" ); document.write( "x+y=21 \n" ); document.write( "y=21-x (equation 1)\r \n" ); document.write( "\n" ); document.write( "5.5x+3.5y=83.5 (sub in equation 1) \n" ); document.write( "5.5x+3.5(21-x)=83.5 \n" ); document.write( "5.5x+73.5-3.5x=83.5 \n" ); document.write( "2x+73.5-73.5=83.5-73.5 \n" ); document.write( "2x=10(divide both sides by 2) \n" ); document.write( "x=5 \n" ); document.write( "21-5 = 16 \n" ); document.write( "Therefore there were 5 adults and 16 childerns\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |