document.write( "Question 19184: A movie theater sells adult tickets at $5.50 a ticket and $3.50 for a childs ticket. How many of each ticket was sold if 21 tickets were bought for $83.50 \n" ); document.write( "
Algebra.Com's Answer #9238 by Paul(988)\"\" \"About 
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adults = x
\n" ); document.write( "childern = y
\n" ); document.write( "x+y=21
\n" ); document.write( "y=21-x (equation 1)\r
\n" ); document.write( "\n" ); document.write( "5.5x+3.5y=83.5 (sub in equation 1)
\n" ); document.write( "5.5x+3.5(21-x)=83.5
\n" ); document.write( "5.5x+73.5-3.5x=83.5
\n" ); document.write( "2x+73.5-73.5=83.5-73.5
\n" ); document.write( "2x=10(divide both sides by 2)
\n" ); document.write( "x=5
\n" ); document.write( "21-5 = 16
\n" ); document.write( "Therefore there were 5 adults and 16 childerns\r
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