document.write( "Question 126066: find the slope, if it exists, of (-1,-2), (3,-2) \n" ); document.write( "
Algebra.Com's Answer #92379 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let's denote the first point (-1,-2) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "Now let's denote the second point (3,-2) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-2--2%29%2F%283--1%29\" Plug in \"y%5B2%5D=-2\",\"y%5B1%5D=-2\",\"x%5B2%5D=3\",\"x%5B1%5D=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=0%2F4\" Subtract the terms in the numerator \"-2--2\" to get \"0\". Subtract the terms in the denominator \"3--1\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=0\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line through the points (-1,-2) and (3,-2) is \"m=0\"
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