document.write( "Question 126063: Hi I'm having trouble with this piecewise function. Can you help me?\r
\n" ); document.write( "\n" ); document.write( "Evaluate the piecewise defined function at the indicated values.
\n" ); document.write( "f(x)={(-5 if x<=3, x + 3 if x>3)
\n" ); document.write( "f(-4) =
\n" ); document.write( "f(0) =
\n" ); document.write( "f(3) =
\n" ); document.write( "f(4) =
\n" ); document.write( "f(6) = \n" ); document.write( "
Algebra.Com's Answer #92374 by marcsam823(57)\"\" \"About 
You can put this solution on YOUR website!
The first rule of this function states that if \"x%3C=3\" the value of the function or f(x) = 5. We see three x values that meet the criteria of being less than or equal to 3: -4,0 & 3. This means that a, b and c below are all equal to 5.
\n" ); document.write( "The other rule states that if x>3 then f(x) = x + 3. We see that two of the x values below are greater than 3: 4 & 6. This means that d & e below are equal to 4 + 3 = 7 and 6 + 3 = 9, respectively.
\n" ); document.write( "Summary:
\n" ); document.write( "f(x)={(-5 if x<=3, x + 3 if x>3)
\n" ); document.write( "a. f(-4) = 5
\n" ); document.write( "b. f(0) = 5
\n" ); document.write( "c. f(3) = 5
\n" ); document.write( "d. f(4) = 7
\n" ); document.write( "e. f(6) = 9
\n" ); document.write( " \n" ); document.write( "
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