document.write( "Question 126021:
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document.write( "The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 38 in., find the width of the rectangle. \n" );
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Algebra.Com's Answer #92347 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+10 THEN THE PERIMETER=2(2W+10)+2W \n" ); document.write( "38=4W+20+2W OR 38-20=6W+2W OR 8W=18 OR W=18/8 OR W=2.25 IN. \n" ); document.write( "PROOF \n" ); document.write( "L=2*2.25+10) OR L=4.5+10 OR L=14.5 \n" ); document.write( "PROOF: \n" ); document.write( "38=2*14.5+2*4.5 OR 38=29+9 OR 38=38 \n" ); document.write( " \n" ); document.write( " |