document.write( "Question 125979: What is the inverse of 8x+7? \n" ); document.write( "
Algebra.Com's Answer #92322 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you mean: \"What is the inverse of y=8x+7?\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=8x%2B7\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=8y%2B7\" Switch the x and y variables\r
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\n" ); document.write( "\n" ); document.write( "\"0=8y%2B7-x\"Subtract x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-8y=7-x\" Subtract 8y from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=%287-x%29%2F%28-8%29\" Divide both sides by -8 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%287%29%2F%28-8%29-%28x%29%2F%28-8%29\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%287%2F8%29%2B%281%2F8%29x\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F8%29x-%287%2F8%29\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So the inverse of \"y=8x%2B7\" is \"y=%281%2F8%29x-%287%2F8%29\"\r
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