document.write( "Question 125965: Ms K is 6 years more than 3 times as old as her daughter. 8 years ago she was 2 years less than 9 times as old as her daughter was then. What are thier ages? \n" ); document.write( "
Algebra.Com's Answer #92313 by ankor@dixie-net.com(22740)\"\" \"About 
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Let k = K's age now; let d = daughter's age now
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\n" ); document.write( "Just write an equation for what it says:
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\n" ); document.write( "\"Ms K is 6 years more than 3 times as old as her daughter.\"
\n" ); document.write( " k = 3d + 6
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\n" ); document.write( "8 years ago they would have been
\n" ); document.write( "(k-8) and (d-8)
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\n" ); document.write( "\"8 years ago she was 2 years less than 9 times as old as her daughter was then.\"
\n" ); document.write( "(k-8) = 9(d-8) - 2
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\n" ); document.write( "k - 8 = 9d - 72 - 2
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\n" ); document.write( "k = 9d - 74 + 8
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\n" ); document.write( "k = 9d - 66
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\n" ); document.write( " What are their ages?
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\n" ); document.write( "Substitute (3d+6) for k in the above equation, find d
\n" ); document.write( "(3d+6) = 9d - 66
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\n" ); document.write( "3d - 9d = -66 - 6
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\n" ); document.write( "-6d = -72
\n" ); document.write( "d = \"%28-72%29%2F%28-6%29\"
\n" ); document.write( "d = +12 yrs is the daughter's age now
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\n" ); document.write( "Mama would be: 36 + 6 = 42 yrs old now
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\n" ); document.write( "Check our solutions in the statement:
\n" ); document.write( "8 years ago she was 2 years less than 9 times as old as her daughter was then.
\n" ); document.write( "(42-8) = 9(12-8) - 2
\n" ); document.write( " 34 = 9(4) - 2; confirms out solutions
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\n" ); document.write( "Could you follow this OK? Any questions?
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