document.write( "Question 125927: After losing 30 pounds, an individual weights 110 pound more than 1/3 his previous weight . Find the previous weight of the individual.
\n" ); document.write( "I tried X/1/3 + 110 \n" ); document.write( "

Algebra.Com's Answer #92307 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let W = the individual's weight, then you can write:
\n" ); document.write( " $\"W-30+=+W%2F3+%2B+110\"$ Multiply through by 3 to clear the fraction.
\n" ); document.write( " $\"3W-90+=+W%2B330\"$ Subtract W from both sides.
\n" ); document.write( " $\"2W-90+=+330\"$ Add 90 to both sides.
\n" ); document.write( " $\"2W+=+420\"$ Finally, divide both sides by 2.
\n" ); document.write( " $\"W+=+210\"$
\n" ); document.write( "The individual previously weighed 210 lbs.
\n" ); document.write( "Check:
\n" ); document.write( " $\"W-30+=+W%2F3+%2B+110\"$ Substitute W = 210
\n" ); document.write( " $\"210-30+=+210%2F3+%2B+110\"$
\n" ); document.write( " $\"180+=+70%2B110\"$
\n" ); document.write( " $\"180+=+180\"$ \n" ); document.write( "

\n" );