document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125943>Question 125943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factoring: quadratic equations and completing the square<BR>\n" );
document.write( "2a^2-5ab-3b^2=0\r<BR>\n" );
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document.write( "would i use complete the square to factor this? I'm not sure. Is there more than one way to do it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92302 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2a^2-5ab-3b^2=0 <BR>\n" );
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document.write( "Use the AC Method<BR>\n" );
document.write( "Your Problem:<BR>\n" );
document.write( "AC = 2*-3 = -6<BR>\n" );
document.write( "B = -5<BR>\n" );
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document.write( "Think of two numbers whose product = AC = -6<BR>\n" );
document.write( "and whose sum is B = -5<BR>\n" );
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document.write( "The numbers are -6 and +1<BR>\n" );
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document.write( "Replace the B-term with the sum: -5ab = -6ab+ab to get:<BR>\n" );
document.write( "2a^2-6ab+ab-3b^2 = 0<BR>\n" );
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document.write( "Factor the 1st two terms and the last two terms separately to get:<BR>\n" );
document.write( "2a(a-3b)+b(a-3b) = 0<BR>\n" );
document.write( "Factor again to get:<BR>\n" );
document.write( "(a-3b)(2a+b) = 0<BR>\n" );
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document.write( "At this point you have factored the left side of the original equation.<BR>\n" );
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document.write( "Therefore:<BR>\n" );
document.write( "a = 3b or a = -b/2<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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