document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125946>Question 125946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't know how to solve this inequalitie.: It gave me this information. y=x^2 , squareroot y= squareroot x^2, squareroot y=|x|<BR>\n" );
document.write( "where therefore since x The question is |x-3|>|2x+1|\r<BR>\n" );
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document.write( "I asked this question before but is there another way to figure this out without graphing like can we actually solve it by doing the math? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92297 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> |x-3|>|2x+1|<BR>\n" );
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document.write( "if x = 0, you get |-3|>|1|, which is true: so x=0 is part of the solution.<BR>\n" );
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document.write( "If both x-3 and 2x+1 are positive you get:<BR>\n" );
document.write( "x-3 > 2x+1<BR>\n" );
document.write( "x<-4<BR>\n" );
document.write( "Testing x=-10 you get:<BR>\n" );
document.write( "|-13| > |-19| which is false.<BR>\n" );
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document.write( "If both x-3 and 2x+1 are negative you get:<BR>\n" );
document.write( "-x+3 > -2x-1<BR>\n" );
document.write( "x > -4<BR>\n" );
document.write( "Testing x=0 you know already this is true so x>-4 is part of the solution.<BR>\n" );
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document.write( "If x-3 is positive and 2x+1 is negative you get:<BR>\n" );
document.write( "x-3 > -2x-1<BR>\n" );
document.write( "3x > 2<BR>\n" );
document.write( "x>2/3<BR>\n" );
document.write( "Testing x=1 you get:<BR>\n" );
document.write( "|1-3| > |2+1| which is false<BR>\n" );
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document.write( "If x-3 is negative and 2x+1 is positive you get:<BR>\n" );
document.write( "-x+3 > 2x+1<BR>\n" );
document.write( "3x<2<BR>\n" );
document.write( "x <2/3<BR>\n" );
document.write( "Testing 0 you know already this is true so x < 2/3<BR>\n" );
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document.write( "Putting that all together you get -4 < x < 2/3<BR>\n" );
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document.write( "PS: Graphing it is easier.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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