document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125919>Question 125919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each compound inequality. Graph solutions set and write in interval notation.\r<BR>\n" );
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document.write( "x + 4 < 0 or 6x > -12\r<BR>\n" );
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document.write( "Okay, I just need to know where to start, because the rule is if there are two inequality signs separated by “or ” (as above) to solve for x in middle and the term “or” also means “union”. What I’m asking is what numbers do I begin with and how do I enter them? The first step to solving? \r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92293 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simply solve each inequality individually and the final solution will be the union of these two solutions\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+4+%3C+0 ALIGN=MIDDLE  ALT=\"x+%2B+4+%3C+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >} Start with the first inequality\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3C0-4 ALIGN=MIDDLE  ALT=\"x%3C0-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >Subtract 4 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3C-4 ALIGN=MIDDLE  ALT=\"x%3C-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms on the right side\r<BR>\n" );
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document.write( "So the first part of our answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3C-4 ALIGN=MIDDLE  ALT=\"x%3C-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x+%3E+-12 ALIGN=MIDDLE  ALT=\"6x+%3E+-12\"   DISABLED_style= \"max-width:90%; height:auto;\" >} Start with the second inequality\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3E%28-12%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x%3E%28-12%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 6 to isolate x \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3E-2 ALIGN=MIDDLE  ALT=\"x%3E-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide\r<BR>\n" );
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document.write( "So the second part of the answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3E-2 ALIGN=MIDDLE  ALT=\"x%3E-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  \r<BR>\n" );
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document.write( "Answer:\r<BR>\n" );
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document.write( "So together the solution is \r<BR>\n" );
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document.write( "So the solution in interval notation is \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-\infty,-4\right) \cup \left(-2,\infty)\">\r<BR>\n" );
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document.write( "Now let's graph the solution set\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C50%2C-14%2C6%2C-10%2C10%2C%0D%0Anumber_line%28500%2C-14%2C6%29%2C%0D%0Acircle%28-4%2C-5.8%2C0.35%29%2C%0D%0Acircle%28-4%2C-5.8%2C0.4%29%2C%0D%0Acircle%28-4%2C-5.8%2C0.45%29%2C%0D%0Ablue%28line%28-4%2C-5%2C-4-10%2C-5%29%29%2C%0D%0Ablue%28line%28-4%2C-6%2C-4-10%2C-6%29%29%2C%0D%0Ablue%28line%28-4%2C-7%2C-4-10%2C-7%29%29%2C%0D%0Ablue%28arrow%28-4%2C-5%2C-4-10.2%2C-5%29%29%2C%0D%0Ablue%28arrow%28-4%2C-5.5%2C-4-10.2%2C-5.5%29%29%2C%0D%0Ablue%28arrow%28-4%2C-6%2C-4-10.2%2C-6%29%29%2C%0D%0A%0D%0Acircle%28-2%2C-5.8%2C0.35%29%2C%0D%0Acircle%28-2%2C-5.8%2C0.4%29%2C%0D%0Acircle%28-2%2C-5.8%2C0.45%29%2C%0D%0Ablue%28line%28-2%2C-5%2C-2%2B10%2C-5%29%29%2C%0D%0Ablue%28line%28-2%2C-6%2C-2%2B10%2C-6%29%29%2C%0D%0Ablue%28line%28-2%2C-7%2C-2%2B10%2C-7%29%29%2C%0D%0Ablue%28arrow%28-2%2C-5%2C-2%2B8.2%2C-5%29%29%2C%0D%0Ablue%28arrow%28-2%2C-5.5%2C-2%2B8.2%2C-5.5%29%29%2C%0D%0Ablue%28arrow%28-2%2C-6%2C-2%2B8.2%2C-6%29%29%0D%0A%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >  Graph of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3C-4 ALIGN=MIDDLE  ALT=\"x%3C-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > (left sided blue region) and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3E-2 ALIGN=MIDDLE  ALT=\"x%3E-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > (right sided blue region) </SPAN>\n" );
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