document.write( "Question 125815: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, and therefore the cost of food for each member increased by $5. How many students attended the get-together? \n" ); document.write( "
Algebra.Com's Answer #92275 by checkley71(8403)\"\" \"About 
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(500/X)+5=500/(X-5)
\n" ); document.write( "(500+5X)/X=500/(X-5) CROSS MULTIPLY.
\n" ); document.write( "(X-5)(500+5X)=500X
\n" ); document.write( "500X-2500+5X^2-25X=500X
\n" ); document.write( "5X^2-25X-2500=0
\n" ); document.write( "5(X^2-5X-500)=0
\n" ); document.write( "5(X-25)(X=20=0
\n" ); document.write( "X-25=0
\n" ); document.write( "X=25 STUDENTS WERE THE ORIGINAL NUMBER.
\n" ); document.write( "SO 25-5=20 IS THE ACTUAL NUMBER WHO ATTENDED.
\n" ); document.write( "PROOF
\n" ); document.write( "500/25+5=500/(25-5)
\n" ); document.write( "20+5=500/20
\n" ); document.write( "25=25
\n" ); document.write( "
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