document.write( "Question 125815: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, and therefore the cost of food for each member increased by $5. How many students attended the get-together? \n" ); document.write( "
Algebra.Com's Answer #92275 by checkley71(8403) ![]() You can put this solution on YOUR website! (500/X)+5=500/(X-5) \n" ); document.write( "(500+5X)/X=500/(X-5) CROSS MULTIPLY. \n" ); document.write( "(X-5)(500+5X)=500X \n" ); document.write( "500X-2500+5X^2-25X=500X \n" ); document.write( "5X^2-25X-2500=0 \n" ); document.write( "5(X^2-5X-500)=0 \n" ); document.write( "5(X-25)(X=20=0 \n" ); document.write( "X-25=0 \n" ); document.write( "X=25 STUDENTS WERE THE ORIGINAL NUMBER. \n" ); document.write( "SO 25-5=20 IS THE ACTUAL NUMBER WHO ATTENDED. \n" ); document.write( "PROOF \n" ); document.write( "500/25+5=500/(25-5) \n" ); document.write( "20+5=500/20 \n" ); document.write( "25=25 \n" ); document.write( " \n" ); document.write( " |