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document.write( "Hi, Can someone assist me with the following problem? x-5/x+4=2/7 \n" );
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Algebra.Com's Answer #92263 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (X-5)/(X+4)=2/7 IF THIS IS THE EQUATION THEN WE HAVE TO CROSS MULTIPLY. \n" ); document.write( "7(X-5)=2(X+4) \n" ); document.write( "7X-35=2X+8 \n" ); document.write( "7X-2X=8+35 \n" ); document.write( "5X=43 \n" ); document.write( "X=43/5 ANSWER. \n" ); document.write( "------------------------------------------ \n" ); document.write( "X-(5/X)+4=2/7 IF THIS IS THE EQUATION THEN: \n" ); document.write( "(X^2-5)/X+4=2/7 \n" ); document.write( "(X^2-5)/X=2/7-4 \n" ); document.write( "(X^2-5)/X=(2-4*7)/7 \n" ); document.write( "(X^2-5)/X=(2-28)/7 \n" ); document.write( "(X^2-5)/X=-26/7 NOW CROSS MULTIPLY. \n" ); document.write( "7(X^2-5)=-26X \n" ); document.write( "7X^2-35+26X=0 \n" ); document.write( "7X^2+26X-35=0USING THE QUADRATIC EQUATION WE GET; \n" ); document.write( " \n" ); document.write( "X=1.05 & -4.76\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |