document.write( "Question 125596: an air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely. \n" ); document.write( "
Algebra.Com's Answer #92262 by ankor@dixie-net.com(22740)\"\" \"About 
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an air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely.
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\n" ); document.write( "The outbound speed: 300 - 30 = 270 mph
\n" ); document.write( "The return speed: 300 + 30 = 330 mph
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\n" ); document.write( "Let d = distance to the point of no return
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\n" ); document.write( "Write a time equation: Time = \"distance%2Fspeed\"
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\n" ); document.write( "Outbound time + return time = 5 hrs
\n" ); document.write( "\"d%2F270\" + \"d%2F330\" = 5
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\n" ); document.write( "Multiply equation by a multiple of 270 and 330, 89100 will do it:
\n" ); document.write( "330d + 270d = 5(89100)
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\n" ); document.write( "600d = 445500
\n" ); document.write( "d = \"445500%2F600\"
\n" ); document.write( "d = 742.5 miles max distance
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\n" ); document.write( "However, they use the word \"safely\", I doubt they would exceed 700 mi from home \n" ); document.write( "
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