document.write( "Question 125881: Factor:\r
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Algebra.Com's Answer #92261 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"1x%5E2%2B7x%2B6\" we can see that the first term is \"1x%5E2\" and the last term is \"6\" where the coefficients are 1 and 6 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 6 to get 6. Now what two numbers multiply to 6 and add to the middle coefficient 7? Let's list all of the factors of 6:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 6:\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 6\r
\n" ); document.write( "\n" ); document.write( "1*6\r
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\n" ); document.write( "\n" ); document.write( "(-1)*(-6)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7\r
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First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 1 and 6 add up to 7 and multiply to 6\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1x%5E2%2B7x%2B6\", replace \"7x\" with \"1x%2B6x\" (notice \"1x%2B6x\" adds up to \"7x\". So it is equivalent to \"7x\")\r
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\n" ); document.write( "\n" ); document.write( "\"1x%5E2%2Bhighlight%281x%2B6x%29%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1x%5E2%2B1x%2B6x%2B6\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%5E2%2B1x%29%2B%286x%2B6%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B1%29%2B6%28x%2B1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"6\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%28x%2B1%29\" Since we have a common term of \"x%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1x%5E2%2B1x%2B6x%2B6\" factors to \"%28x%2B6%29%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1x%5E2%2B7x%2B6\" factors to \"%28x%2B6%29%28x%2B1%29\" (since \"1x%5E2%2B7x%2B6\" is equivalent to \"1x%5E2%2B1x%2B6x%2B6\")\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B7x%2B6\" factors to \"%28x%2B6%29%28x%2B1%29\"
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