document.write( "Question 125883: Factor:\r
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Algebra.Com's Answer #92259 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"1x%5E2%2B5x%2B6\" we can see that the first term is \"1x%5E2\" and the last term is \"6\" where the coefficients are 1 and 6 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 6 to get 6. Now what two numbers multiply to 6 and add to the middle coefficient 5? Let's list all of the factors of 6:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 6:\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 6\r
\n" ); document.write( "\n" ); document.write( "1*6\r
\n" ); document.write( "\n" ); document.write( "2*3\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-6)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-3)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 5? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 5\r
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First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 2 and 3 add up to 5 and multiply to 6\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1x%5E2%2B5x%2B6\", replace \"5x\" with \"2x%2B3x\" (notice \"2x%2B3x\" adds up to \"5x\". So it is equivalent to \"5x\")\r
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\n" ); document.write( "\n" ); document.write( "\"1x%5E2%2Bhighlight%282x%2B3x%29%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1x%5E2%2B2x%2B3x%2B6\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%5E2%2B2x%29%2B%283x%2B6%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29%2B3%28x%2B2%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%28x%2B2%29\" Since we have a common term of \"x%2B2\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1x%5E2%2B2x%2B3x%2B6\" factors to \"%28x%2B3%29%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1x%5E2%2B5x%2B6\" factors to \"%28x%2B3%29%28x%2B2%29\" (since \"1x%5E2%2B5x%2B6\" is equivalent to \"1x%5E2%2B2x%2B3x%2B6\")\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B5x%2B6\" factors to \"%28x%2B3%29%28x%2B2%29\"
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