document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125866>Question 125866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello <BR>\n" );
document.write( "Please solve . Given the functions f(x) =5x + 17 and g(x)= 6x^2 -7x-3 find (f/g)(x) and the domain of f/g.\r<BR>\n" );
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document.write( "Sorry about the mixup.\r<BR>\n" );
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document.write( "Thanking you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92245 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the functions f(x) =5x + 17 and g(x)= 6x^2 -7x-3 find (f/g)(x) and the domain of f/g. <BR>\n" );
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document.write( "f/g = f(x)/g(x) = (5x+17)/[(2x-3)(3x+1)]<BR>\n" );
document.write( "Domain of f/g is \"all Real Numbers except x = 3/2 and x = -1/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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