document.write( "Question 125858: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30ft by 40ft. The total area, garden plus walkway, is to be 1800ft^2. What must be the width of the walkway to the nearest thousandth? \n" ); document.write( "
Algebra.Com's Answer #92241 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (30+2x)(40+2x)=1,800 \n" ); document.write( "1,200+80x+60x+4x^2=1,800 \n" ); document.write( "4x^2+140x+1,200-1,800=0 \n" ); document.write( "4x^2+120x-600=0 \n" ); document.write( "4(x^2+30x-150)=0 \n" ); document.write( "using the quadratic equation: \n" ); document.write( "x=(-30+-sqrt[30^2-4*1*-150])/2*1 \n" ); document.write( "x=(-30+-sqrt[900+600])/2 \n" ); document.write( "x=(-30+-sqrt1500)/2 \n" ); document.write( "x=(-30+-38.73)/2 \n" ); document.write( "x=(-30+38.73)/2 \n" ); document.write( "x=8.73/2 \n" ); document.write( "x=4.365 ft is the width of the walkway. \n" ); document.write( " \n" ); document.write( " |