document.write( "Question 125858: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30ft by 40ft. The total area, garden plus walkway, is to be 1800ft^2. What must be the width of the walkway to the nearest thousandth? \n" ); document.write( "
Algebra.Com's Answer #92241 by checkley71(8403)\"\" \"About 
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(30+2x)(40+2x)=1,800
\n" ); document.write( "1,200+80x+60x+4x^2=1,800
\n" ); document.write( "4x^2+140x+1,200-1,800=0
\n" ); document.write( "4x^2+120x-600=0
\n" ); document.write( "4(x^2+30x-150)=0
\n" ); document.write( "using the quadratic equation:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" we get:
\n" ); document.write( "x=(-30+-sqrt[30^2-4*1*-150])/2*1
\n" ); document.write( "x=(-30+-sqrt[900+600])/2
\n" ); document.write( "x=(-30+-sqrt1500)/2
\n" ); document.write( "x=(-30+-38.73)/2
\n" ); document.write( "x=(-30+38.73)/2
\n" ); document.write( "x=8.73/2
\n" ); document.write( "x=4.365 ft is the width of the walkway.
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