document.write( "Question 125848This question is from textbook Algebra Structure and Method
\n" ); document.write( ": I have been having trouble figuring out this problem and I was wondering if anyone could help me? I would deeply appreciate it!!! Please and Thank You!!\r
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\n" ); document.write( "\n" ); document.write( "Solving Problems Involving Inequalities\r
\n" ); document.write( "\n" ); document.write( "Solve.
\n" ); document.write( "Randy walked at the rate of 5.2km/h in a straight path from his campsite to a ranch. He returned immediately on horseback at the rate of 7.8km/h. Upon his return, he found that he had been gone for no more than 3.5h. At most how far is it from his campsite to the ranch? \n" ); document.write( "
Algebra.Com's Answer #92232 by checkley71(8403)\"\" \"About 
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D=RT
\n" ); document.write( "D=5.2X GOING.
\n" ); document.write( "D=7.8(3.5-X) RETURNING.
\n" ); document.write( "SEEING AS THE DISTANCES ARE THE SAME WE HAVE:
\n" ); document.write( "5.2X=7.8(3.5-X)
\n" ); document.write( "5.2X=27.3-7.8X
\n" ); document.write( "5.2X+7.8X=27.3
\n" ); document.write( "13X=27.3
\n" ); document.write( "X=27.3/13
\n" ); document.write( "X=2.1 HOURS FOR THE GOING TRIP
\n" ); document.write( "3.5-2.1=1.4 HOURS FOR THE RETURN TRIP.
\n" ); document.write( "PROOF
\n" ); document.write( "5.2*2.1=7.8*1.4
\n" ); document.write( "10.92=10.92 MILES FROM THE CAMP SITE TO THE RANCH.\r
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