document.write( "Question 125770: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #92231 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let x=\"amount @ 15%\", so 10000-x=\"amount @ 14%\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(15%)x+(14%)(10000-x)=1430 __.15x+1400-.14x=1430 __ .01x=30 \n" ); document.write( " |