document.write( "Question 125553: This problem is not in a book it is a hand out.\r
\n" ); document.write( "\n" ); document.write( "If the mixture is P% gasoline, prices at $1.60 per gallon, and (100-P)% alcohol, priced at $1.00 per gallon, write a formula for the price of a gallon of gasahol. \n" ); document.write( "
Algebra.Com's Answer #92226 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
This problem is not in a book it is a hand out.
\n" ); document.write( "If the mixture is P% gasoline, prices at $1.60 per gallon, and (100-P)% alcohol,
\n" ); document.write( " priced at $1.00 per gallon, write a formula for the price of a gallon of gasahol.
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\n" ); document.write( "p = per cent gasoline
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\n" ); document.write( "f(p) = price of a gallon of gasahol.
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\n" ); document.write( "f(p) = \"%28%281.6p%29%29%2F100\" + \"%281%28100-p%29%29%2F100\"; is the gasahol formula
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\n" ); document.write( "We can test our formula using 50% gasoline, it should be $1.30
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\n" ); document.write( "f(50) = \"%28%281.6%2850%29%29%29%2F100\" + \"%281%28100-50%29%29%2F100\"
\n" ); document.write( "f(50) = \"80%2F100\" + \"50%2F100\"
\n" ); document.write( "f(50) = .80 + .50
\n" ); document.write( "f(50) = $1.30 \n" ); document.write( "
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