document.write( "Question 125838: I can't figure this out for the life of me...HELP!!! This has to do with direct and inverse variation.\r
\n" ); document.write( "\n" ); document.write( "The problem is: x varies directly as the square of s and inversely as t. How does x change when s is doubled? When both s and t are doubled?\r
\n" ); document.write( "\n" ); document.write( "Please help me.
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Algebra.Com's Answer #92209 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You can express \"x varies as the square of s and inversely as t\" like this:
\n" ); document.write( "\"x+=+ks%5E2%2Ft\" k is the constant of variation.
\n" ); document.write( "To see how x changes when s is doubled (2s), simply substitute 2s for s in the above formula and simplify.
\n" ); document.write( "\"x+=+k%282s%29%5E2%2Ft\"
\n" ); document.write( "\"x+=+k%284s%5E2%29%2Ft\"
\n" ); document.write( "\"x+=+4%28ks%5E2%2Ft%29\" but, as you can see, the factor in parentheses (\"ks%5E2%2Ft\") is the original x, so...
\n" ); document.write( "\"x+=+4x\" or, in words, x is quadrupled when s is doubled.
\n" ); document.write( "Now, when both s and t are doubled, substitute 2s and 2t for s and t respectively in the first formula:
\n" ); document.write( "\"x+=+ks%5E2%2Ft\"
\n" ); document.write( "\"x+=+k%282s%29%5E2%2F2t\" Simplify.
\n" ); document.write( "\"x+=+k%284s%5E2%29%2F2t\" Cancel 2's in the top and bottom.
\n" ); document.write( "\"x+=+2%28ks%5E2%2Ft%29\" or...
\n" ); document.write( "\"+x+=+2x\" so you see that x is doubled when both s and t are doubled.
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