document.write( "Question 802: If a vehicle was purchased for $12590.00, which was 20% off the original price, what was the original price? \n" ); document.write( "

Algebra.Com's Answer #922 by longjonsilver(2297) $\"\"$ $\"About$

You can put this solution on YOUR website!
the other answer is so badly wrong, i cannot believe it!\r
\n" ); document.write( "\n" ); document.write( "Let x = original price.\r
\n" ); document.write( "\n" ); document.write( "The long way (and safest way) is as follows:\r
\n" ); document.write( "\n" ); document.write( "Find what 20% of the original is.
\n" ); document.write( "Subtract this from the original
\n" ); document.write( "that answer is equal to 12590\r
\n" ); document.write( "\n" ); document.write( "so...what is 20% of x?...answer is (20/100)*x which is 0.2x\r
\n" ); document.write( "\n" ); document.write( "original minus the 20% discount is (x - 0.2x) which is 0.8x and this is equal to the price of $12590\r
\n" ); document.write( "\n" ); document.write( "so 0.8x = 12590 --line A
\n" ); document.write( "therefore x = 12590/0.8
\n" ); document.write( "x = 15737.50\r
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\n" ); document.write( "Quick method.... a % reduction is less than 1 at line A...10% reduction would be 0.9, 25% reduction would be 0.75 etc\r
\n" ); document.write( "\n" ); document.write( "An increase would therefore be greater than 1, eg 10% increase is 1.10. 3% increase is 1.03 (NOT 1.3)
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\n" ); document.write( "\n" ); document.write( "jon \n" ); document.write( "

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