document.write( "Question 125606: a new machine can make 10000 cans three times faster than an older one. With both machines working ,10000 cans can be made in 9 hrs. How long would it take the new machine, working alone to make 10000 cans? \n" ); document.write( "
Algebra.Com's Answer #92193 by ankor@dixie-net.com(22740)\"\" \"About 
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a new machine can make 10000 cans three times faster than an older one. With both machines working ,10000 cans can be made in 9 hrs. How long would it take the new machine, working alone to make 10000 cans?
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\n" ); document.write( "Let x = time for the new machine to do the job by itself
\n" ); document.write( "then
\n" ); document.write( "3x = time required for the old machine to do the job by itself, (take 3 times as long)
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\n" ); document.write( "Let the completed job = 1; (the making of 10,000 cans)
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\n" ); document.write( "\"9%2F%283x%29\" + \"9%2Fx\" = 1
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\n" ); document.write( "Multiply equation to get rid of the denominators and you have:
\n" ); document.write( "9 + 3(9) = 3x
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\n" ); document.write( "9 + 27 = 3x
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\n" ); document.write( "36 = 3x
\n" ); document.write( "x = \"36%2F3\"
\n" ); document.write( "x = 12 hrs, new machine working by itself
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\n" ); document.write( "Check solution in original equation (old machine time 3*12 = 36hrs)
\n" ); document.write( "\"9%2F36\" + \"9%2F12\" = 1
\n" ); document.write( "\"1%2F4\" + \"3%2F4\" = 1
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