document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125808>Question 125808</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321269470/algebrahomeworkh>Introductory Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> If anyone could help me with this problem, it would be greatly appreciated.  The problem reads:  A polynomial in x has degree 3.  The coefficient of x^2 is 3 less than the coefficient of x^3.  The coefficient of x is three times the coefficient of x^2.  The remaining coefficient is 2 more than the coefficient of x^3.  The sum of the coefficient is -4.  Find the polynomial. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92191 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The problem reads: \"A polynomial in x has degree 3.\" Write it:<BR>\n" );
document.write( "ax^3 + bx^2 + cx + d<BR>\n" );
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document.write( "The coefficient of x^2 is 3 less than the coefficient of x^3.<BR>\n" );
document.write( "b = a - 3<BR>\n" );
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document.write( " The coefficient of x is three times the coefficient of x^2.<BR>\n" );
document.write( "c = 3b<BR>\n" );
document.write( "also, substituting (a-3) for b<BR>\n" );
document.write( "c = 3(a-3)<BR>\n" );
document.write( "c = 3a - 9<BR>\n" );
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document.write( "The remaining coefficient is 2 more than the coefficient of x^3.<BR>\n" );
document.write( "d = a + 2<BR>\n" );
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document.write( " The sum of the coefficient is -4. <BR>\n" );
document.write( "a + b + c + d =-4<BR>\n" );
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document.write( "Using the 1st 3 equations, substitute for b, c, d:<BR>\n" );
document.write( "a + (a-3) + (3a-9) + (a+2) = -4<BR>\n" );
document.write( "a + a - 3 + 3a - 9 + a + 2 = -4<BR>\n" );
document.write( "we gather together:<BR>\n" );
document.write( "a + a + 3a + a - 3 - 9 + 2 = - 4<BR>\n" );
document.write( "6a - 10 = -4<BR>\n" );
document.write( "6a = -4 + 10<BR>\n" );
document.write( "6a = 6<BR>\n" );
document.write( "a = 1<BR>\n" );
document.write( "Then using the 1st 3 equations, substituting 1 for a<BR>\n" );
document.write( "b = 1 - 3<BR>\n" );
document.write( "b = -2<BR>\n" );
document.write( "and<BR>\n" );
document.write( "c = 3(1) - 9<BR>\n" );
document.write( "c = -6<BR>\n" );
document.write( "and<BR>\n" );
document.write( "d = 1 + 2<BR>\n" );
document.write( "d = 3<BR>\n" );
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document.write( "Find the polynomial.<BR>\n" );
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document.write( "y = x^2 - 2x^2 - 6x + 3 </SPAN>\n" );
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