document.write( "Question 125803: Kevin is three times as old as Bob. Three years ago the sum of their ages was 22yr. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #92184 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"Kevin is three times as old as Bob.\" \n" ); document.write( " k = 3b \n" ); document.write( ": \n" ); document.write( "Three years ago, their ages; \n" ); document.write( "(k-3) and (b-3), right? \n" ); document.write( ": \n" ); document.write( "\"Three years ago the sum of their ages was 22yr.\" \n" ); document.write( "(k-3) + (b-3) = 22 \n" ); document.write( ": \n" ); document.write( "k - 3 + b - 3 = 22 \n" ); document.write( ": \n" ); document.write( "k + b - 6 = 22 \n" ); document.write( ": \n" ); document.write( "k + b = 22 + 6 \n" ); document.write( ": \n" ); document.write( "k + b = 28 \n" ); document.write( ": \n" ); document.write( "How old is each now? \n" ); document.write( ": \n" ); document.write( "Substitute 3b for k, find b \n" ); document.write( "3b + b = 28 \n" ); document.write( ": \n" ); document.write( "4b = 28 \n" ); document.write( "b = \n" ); document.write( "b = 7 yrs old is Bob \n" ); document.write( "then \n" ); document.write( "3(7) = 21 yrs old is Kevin \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solution using the statement: \n" ); document.write( "\"Three years ago the sum of their ages was 22yr. \" \n" ); document.write( "(21-3) + (7-3) = \n" ); document.write( "18 + 4 = 22; confirms our solution \n" ); document.write( ": \n" ); document.write( "Not that hard, do you think? \n" ); document.write( " |